Finding extrema

Answer all the questions below and press submit to see how many you got right.

id: 21363

We want to find the minimum of the function $f(x)=x^2-6x+13.$ What is the derivative $f^{\prime}?$

  • $2x-6$
    $-6x+13$
    $x^2-6$
    $\frac{1}{3}x^3-3x^2+13x$